moll had some 10 cent coins and 50 cent coins in his savings bank . he had more 10 cent coins than 50 cent coins. the total value of the coins was $15.80.what was the total number of coins that moll had.

Guest Mar 13, 2017

#1**+5 **

moll had some 10 cent coins and 50 cent coins in his savings bank . he had more 10 cent coins than 50 cent coins. the total value of the coins was $15.80.what was the total number of coins that moll had.

10T +50F = 1580 T > F

T +5F = 158

One solution would be T=158 and F=0

10(158 - 5a ) +50( b ) =1580

158, 0

153, 1 = 154 coins

148, 2 = 150 coins

143, 3 = 146 coins

138, 4 = 144 coins

133, 5 = 138 coins

128, 6 = 134 coins

123, 7

118, 8

113, 9

108, 10

103, 11

98, 12

93, 13

88, 14

83, 15

78, 16

73, 17

68, 18

63, 19

58, 20

53, 21

48, 22

43, 23

38, 24

33, 25 58 coins

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(154-58)/4 = 96/4 = 24

So there are many answers all of the form

58+4k where k is any integer and \(0\le k \le 24\)

Melody
Mar 13, 2017