+0  
 
0
226
1
avatar

moll had some 10 cent coins and 50 cent coins in his savings bank . he had more 10 cent coins than 50 cent coins. the total value of the coins was $15.80.what was the total number of coins that moll had.

Guest Mar 13, 2017
 #1
avatar+93305 
+5

moll had some 10 cent coins and 50 cent coins in his savings bank . he had more 10 cent coins than 50 cent coins. the total value of the coins was $15.80.what was the total number of coins that moll had.

 

10T +50F = 1580           T > F

T     +5F   =  158

 

 

One solution would be T=158 and F=0

 

10(158 -  5a      ) +50(     b    ) =1580

 

158,  0

153,  1   =   154 coins

148,  2    =  150 coins

143,  3  =   146 coins

138,  4   =   144 coins

133,  5   =   138 coins

128,  6   =   134 coins

123,  7

118,  8

113,  9

108, 10

103,  11

98,    12

93,    13

88,    14

83,    15

78,    16

73,    17

68,    18

63,     19

58,     20  

53,     21

48,     22

43,     23

38,     24

33,     25         58 coins

------------------------------------

(154-58)/4 =  96/4  =  24

 

 

So there are many answers all of the form      

58+4k       where k is any integer and      \(0\le k \le 24\)

Melody  Mar 13, 2017

8 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.