+1452 In the diagram, four circles of radius 4 units intersect at the origin. What is the number of square units in the area of the shaded region? Express your answer in terms of pi.
Thanks!
+129928 Look at the diagram, ACG
The area between chord BC and the edge of the top circle can be found as
Area of sector ABC - area of triangle ABC =
(1/4)pi (4)^2 - (1/2)(4^2)sin (90°) =
[ 4pi - 8 ] units^2
And due to symmetry.....we would have 8 of these areas....so....the total area of the shaded regions is
8 ( 4pi - 8 ) =
[ 32 pi - 64] units ^2
