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If the equation of motion of a particle is given by s=Acos(wt+sigma), the particle is said to undergo simple harmonic motion.

Find the velocity of the particle at time t.

s'(t)= 

when is the velocity 0? use n as the arbitrary integer.

 

I asked this question before because I cannot figure out what I am doing wrong, when I use the chain rule. The answers that was given before was wrong.

 Sep 26, 2016

Best Answer 

 #1
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Well the chain rule is f(g(x))' = f'(g(x)) × g'(x)

 

The derivative of the cos function is the negative sin function. So the first part is -Asin(wt + sigma)

 

Then take the derivative of the function inside the parenthesis to get w since the derivative of wt with respect to the is w, and the derivative of sigma is 0 assuming it is a constant.

 

Therefore the derivative of the entire function is -Awsin(wt + sigma).

 

This may be wrong since I am just learning about derivatives, but it is what I would do.

 Sep 26, 2016
edited by Skgr136  Sep 26, 2016
 #1
avatar+223 
0
Best Answer

Well the chain rule is f(g(x))' = f'(g(x)) × g'(x)

 

The derivative of the cos function is the negative sin function. So the first part is -Asin(wt + sigma)

 

Then take the derivative of the function inside the parenthesis to get w since the derivative of wt with respect to the is w, and the derivative of sigma is 0 assuming it is a constant.

 

Therefore the derivative of the entire function is -Awsin(wt + sigma).

 

This may be wrong since I am just learning about derivatives, but it is what I would do.

Skgr136 Sep 26, 2016
edited by Skgr136  Sep 26, 2016

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