Adult ticket costs = $3
Child ticket cost = $12
Adult food = $8
Child food = $4
Adult profit = $5
Child profit = $10
Maximum of 300 tickets
Ticket sales must be at least $900
Food sales must be at least $1000
Cannot be more than 3 children’s tickets per adult ticket sold.
(These are the graphs that I got I feel like I'm missing some)
x>0 (cannot have negative tickets)
y>0 (cannot have negative tickets)
x+y<300 ( maximum of 300 tickets)
3x+12y>900 ( ticket sales)
8x+4y>1000 (food sales)
Optimisation function = Profit = 5x+10y
Find out the maximum profit the theatre could expect.
Have I missed a grpah line and would I put the food line and ticket line on the same graph?
