What is the sum of A and B if \(\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot\frac{6}{5}\cdot\ldots\cdot\frac{a}{b}=9\)
Notice that the numerator of each term cancels with the denominator of the next term, so that overall you are left with \(\frac{a}{2}=9\)
Hence a = 18. The denominator of each term is just 1 less than the numerator, so b = a-1 = 17.
Thank you so much Alan
+182 
