For what value of the constant $c$ does the system \begin{align*} 3x + 4y &= 7,\\ 6x + 4y &= c- 4y, \end{align*}have infinitely many solutions?

Guest Oct 23, 2017

#1**+2 **

3x + 4y = 7

6x + 4y = c - 4y → 6x + 8y = c

The second equation will be a multiple of the first when c = 14

And this value of c will result in infinite solutions for the system

CPhill
Oct 23, 2017

#2**+1 **

My mind is blown

For what value of the constant $c$ does the system \begin{align*} 3x + 4y &= 7,\\ 6x + 4y &= c- 4y, \end{align*}have infinitely many solutions?

Hello guest!

\( 3x + 4y = 7,\\ 6x + 4y = c- 4y \)

\(3x+4y=\frac{c}{2}\\ \frac{c}{2}=7\\ \color{blue} c=14 \)

At c = 14 this system of equations has infinitely many results.

!

asinus
Oct 23, 2017