+0

# mymaths

#1
+10

We can divide this up a bit.

2x+13<6x+1

AND

6x+1<4x+11

First, solve 2x+13<6x+1.

2x+13<6x+1

Subtract 1 from each side...

2x+12<6x

Subtract 2x from each side...

12<6x

Divide by 6 on each side...

2<x

There you go! Now, let's do 6x+1<4x+11.

6x+1<4x+11

Subtract 1 from each side...

6x<4x+10

Subtract 4x from each side...

2x<10

Divide by 2 on each side...

x<5

Okay! Now we know that 2<x and x<5.

In conclusion, 2<x<5.

Nov 26, 2015

#1
+10

We can divide this up a bit.

2x+13<6x+1

AND

6x+1<4x+11

First, solve 2x+13<6x+1.

2x+13<6x+1

Subtract 1 from each side...

2x+12<6x

Subtract 2x from each side...

12<6x

Divide by 6 on each side...

2<x

There you go! Now, let's do 6x+1<4x+11.

6x+1<4x+11

Subtract 1 from each side...

6x<4x+10

Subtract 4x from each side...

2x<10

Divide by 2 on each side...

x<5

Okay! Now we know that 2<x and x<5.

In conclusion, 2<x<5.

Anonymous4338 Nov 26, 2015
#2
0

Very nice, Anonymous4338..........5 pts from me.....!!!   Nov 26, 2015