**What is the rectangular form of the polar equation?**

**θ=−5π/6**

- y=−3√3x

- y=−3√x

- y=3√3x

- y=3√x

Guest May 3, 2022

#1**0 **

Note that (x, y) = (r cos θ, r sin θ) = (r cos(−5π/6), r sin(−5π/6)) = \(\left(-\dfrac{r\sqrt3}2, -\dfrac{r}2\right)\) is on the graph of \(\theta = -\dfrac{5\pi}6\).

Let t = -r/2 and we have \((x(t), y(t)) = (t\sqrt 3, t)\).

Which straight line has this parametric equation?

Edit: I realized that the answer is not in the options.

MaxWong May 3, 2022