How many ways can you write two different letters, so that they are in alphabetical order? For example, AB and CT count, but ZA does not.?
We can also note that to form a sequence with two different letters in alphabetical order, we need first pick the letters we'll use, then put them in order. We can choose two letters to use in \($\binom{26}{2} = 325$\) ways, and there's only 1 way to put each pair in order.
Hence, there are 325 sequences that fit the problem.
I'm guessing...
A followed by any other letter is a valid possibility. B followed by any letter except A or B is a valid possibility.
With A there are 25 possibilities, with B there are 24 possibilities, with C there are 23, etc.
25 + 24 + 23 + 22 + 21 + . . . + 3 + 2 + 1 = (1/2)(25)(25 + 1) = 325