How do I solve ln(x-9)^4=8?
\(\ln(x-9)^4=8\\ \ln(x-9)=\pm 8^{\frac 1 4} = \pm 2^{\frac 3 4} \\ x-9 = e^{\pm 2^{\frac 3 4}} \\ x = 9+e^{\pm 2^{\frac 3 4}}\)
Hi Rom, it is good to see you here :)
It's possible this was meant as \(\ln((x-9)^4)=8\)
in which case we have \(4\ln(x-9)=8\rightarrow \ln(x-9)=2\rightarrow x-9=e^2\rightarrow x=9+e^2\)
