Natural Log Equation

How do I solve ln(x-9)^4=8?

$\ln(x-9)^4=8\\ \ln(x-9)=\pm 8^{\frac 1 4} = \pm 2^{\frac 3 4} \\ x-9 = e^{\pm 2^{\frac 3 4}} \\ x = 9+e^{\pm 2^{\frac 3 4}}$ 

Hi Rom, it is good to see you here  :)

It's possible this was meant as        $\ln((x-9)^4)=8$

in which case we have      $4\ln(x-9)=8\rightarrow \ln(x-9)=2\rightarrow x-9=e^2\rightarrow x=9+e^2$