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# natural log

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+790

Hi friends,

I promise..only 2 more questions....

I have a basic understanding of natural logs, the expression being ln, which is the same as log with base e...and so on...I am just not sure how to handle this one:

Solve the following using natural logs:

$$A={{1.15^2* \sqrt{5.4}} \over6.21}$$

All and any help is always greatly appreciated!

Oct 21, 2020

#1
+112504
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Are you sure you have copied this down properly Juriemagic?

Oct 21, 2020
#2
+112504
+1

I really do not know what you are expected to do here.

Maybe

$$A={{1.15^2* \sqrt{5.4}} \over6.21}\\ lnA=ln1.15^2+ln5.4^{0.5}-ln6.21\\ lnA=2ln1.15+0.5ln5.4-ln6.21\\ lnA\approx -0.7034..\\ A\approx 0.49488$$

Why anyone would bother with that I have no idea.

The exact answer, without logs, is   $$\frac{23\sqrt{15}}{180}$$

LaTex

A={{1.15^2* \sqrt{5.4}} \over6.21}\\
lnA=ln1.15^2+ln5.4^{0.5}-ln6.21\\
lnA=2ln1.15+0.5ln5.4-ln6.21\\
lnA\approx -0.7034..\\
A\approx 0.49488

Oct 21, 2020
#3
+790
+1

hi Melody,

yes, it was copied correctly....Thank you for the answer....

juriemagic  Oct 21, 2020