Hi friends,
I have something that tickles me....please help:
if I look at \(x^2-4x-5=0\)
and I wanted to check the nature of the roots by solving the equation, it would be like this:
\((x+1)(x-5)=0\)
\(x=-1\) or \(x=5\)
So all I can really say is that the roots are un-equal
However doing it this way:
\(\Delta =b^2-4ac\)
\(=(-4)^2-4(1)(-5)\)
\(=16+20\)
\(=36\)
which means the roots will be real, un-equal and rational...However, the roots do only seem to satisfy the "un-equal" nature?
Notice though that b^2 -4ac is under a radical......so sqrt (36) = 6
So.....the roots will be real, rational AND unequal
Hi CPhill,
thank you for the response, I guess I'm getting thrown off track with the fact that I thought the roots had to be squares themselves. my error, thank you kindly..