I have attempted to solve this problem but I need some help. "The problem stated Let F(x)=x²-10 and G(x)=2-x
It is asking me to Find (f/g)(-6).
F(x)=x²-10 and G(x)=2-x
(f/g)(x) = x^2-10 / (2 - x)
(f/g)(-6) = (-6^2) - 10 / (2 - (-6))
= 36 - 10 / (8)
= 26/8.*
Another method as follows:
F(x)=x²-10 and G(x)=2-x
f(-6) = (-6)^2 - 10 = 36 - 10 = 26
g(-6) = 2 - (-6) = 8
f(-6) / g(-6) = 26/8.*
*(f/g)(-6) = f(-6)/g(-6)
F(x)=x²-10 and G(x)=2-x
(f/g)(x) = x^2-10 / (2 - x)
(f/g)(-6) = (-6^2) - 10 / (2 - (-6))
= 36 - 10 / (8)
= 26/8.*
Another method as follows:
F(x)=x²-10 and G(x)=2-x
f(-6) = (-6)^2 - 10 = 36 - 10 = 26
g(-6) = 2 - (-6) = 8
f(-6) / g(-6) = 26/8.*
*(f/g)(-6) = f(-6)/g(-6)