+0  
 
0
300
14
avatar+1828 

I need help in these questions in details  

and Please understand that I struggle a little with English

 

 

 

I determine the velocity is negative because the slope is negative ! I chose (b) .. right ? 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

physics
xvxvxv  Aug 26, 2014

Best Answer 

 #12
avatar+26322 
+10

17) is c.

I think all the others have been answered.

Alan  Aug 26, 2014
Sort: 

14+0 Answers

 #1
avatar+8 
+5

the answer
length = + 5
time = +2
v= 5/2 = + 2.5

aliammar  Aug 26, 2014
 #2
avatar+8 
+5

the length still bositive any way the direction is nigative or not 

aliammar  Aug 26, 2014
 #3
avatar+90988 
+10

Question 5 is right.  

 

Question 11   There may be a 'normal' method for doing this, I am not a physics specialist.

 

$$magnitude\\
=\sqrt{7.6^2+5.2^2}\\
=9.20869\\
=9.2$$

 

$$\\tan\theta=\frac{5.2}{7.6}$$

 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{5.2}}}{{\mathtt{7.6}}}}\right)} = {\mathtt{34.380\: \!344\: \!723\: \!845^{\circ}}}$$

direction = 180+34.38 = 214.38 degrees

 

So the answer is B      9.2 and 214.38 degrees with the positive x axis.

 

If you do not understand what I have done then make sure you ask me to explain more.  

Melody  Aug 26, 2014
 #4
avatar+1828 
0

Thank you aliammar 

 

Melody .. its very clear .. the mistake that I do un my solution that I took this angle 

 

 

xvxvxv  Aug 26, 2014
 #5
avatar+90988 
+10

Good,

Lets try question 16

easterly force = 3N

Northerly force =4N

Use Pythagoras's theorem to get net force.

sqrt(9+16)=5N

Now,  F=ma

5=2*a

$$acceleration =5/2=2.5m/s^2$$

Melody  Aug 26, 2014
 #6
avatar+90988 
+10

Question 19

 

NOTE:    I do not know this stuff.  I am referencing this site

http://zonalandeducation.com/mstm/physics/mechanics/forces/newton/mightyFEqMA/mightyFEqMA.html

It looks pretty good.  

u=30m/s,  mass=2000kg,  Braking force=10000N,  v=0,   find t

F=ma    therefore a=F/m=-10000/2000=-5m/s2

v=u+at

0=30-5t

5t=30

t=6 seconds

------------

d=ut+(1/2)at2

d=30*6+(1/2)(-5)*36

d=180+-90

distance=90metres      I think that D is the answer.

-------------

Melody  Aug 26, 2014
 #7
avatar+1828 
0

for 16 .. Now its very clear  thank you 

xvxvxv  Aug 26, 2014
 #8
avatar+90988 
+5

I don't know question 17 sorry.

Melody  Aug 26, 2014
 #9
avatar+1828 
0

for 19 .... also now its very clear 

xvxvxv  Aug 26, 2014
 #10
avatar+26322 
+10

For question 5) the average velocity is (x(4secs) - x(2secs))/(4secs - 2secs)

This is (5 - 10)/(4 - 2) = -5/2 = -2.5 m/s

So b is the correct answer.

Alan  Aug 26, 2014
 #11
avatar+1828 
0

Thank you alan ... waiting for remaining questions 

xvxvxv  Aug 26, 2014
 #12
avatar+26322 
+10
Best Answer

17) is c.

I think all the others have been answered.

Alan  Aug 26, 2014
 #13
avatar+90988 
+5

Thanks Alan.  

Melody  Aug 27, 2014
 #14
avatar+1828 
0

Thanks for all ... alan and melody 

xvxvxv  Aug 28, 2014

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