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Nebraska, the home of the AMC, changed its license plate scheme. Each old license plate consisted of a letter followed by four digits. Each new license plate consists of three letters followed by three digits. If $a$ is the number of possible license plates in the old scheme and $b$ is the number of possible license plates in the new scheme, what is the value of $b/a$? Express your answer as a decimal to the nearest tenth.

 Apr 7, 2015

Best Answer 

 #1
avatar+129845 
+10

The number of old license plates possible in the old system.......assuming digit repeats, is given by

26 x 10000  =  260,000

The number of license plates possible in the new system......assuming letter and digit repeats... is given by

(26)^3 * 1000 = 17,576, 000

So

260,000 / 17,576,000 = 0.0148     {rounding this to the nearest tenth  = 0 !!! }

 

  

 Apr 7, 2015
 #1
avatar+129845 
+10
Best Answer

The number of old license plates possible in the old system.......assuming digit repeats, is given by

26 x 10000  =  260,000

The number of license plates possible in the new system......assuming letter and digit repeats... is given by

(26)^3 * 1000 = 17,576, 000

So

260,000 / 17,576,000 = 0.0148     {rounding this to the nearest tenth  = 0 !!! }

 

  

CPhill Apr 7, 2015
 #2
avatar+83 
0

I'm sorry, but this answer was incorrect. I don't understand why. :(

 Apr 7, 2015
 #3
avatar+129845 
+5

Me, neither....unless we're assuming that letters and/or digits can't be repeated......do you know if that's the assumption ???

 

  

 Apr 7, 2015
 #4
avatar+83 
0

Maybe. It isn't very specific. Thanks still, CPhill!

 Apr 7, 2015
 #5
avatar+83 
0

I hVe one more try to get it right.

 Apr 7, 2015
 #6
avatar+129845 
+5

Oops...I mis-read this...... it was supposed to be    $b$/ $a$   ...!!!

 

Let  me revise my answer as

17, 576,000 / 260,000  = 67.6

 

Sorry....Looloo   !!!!!

 

  

 Apr 8, 2015
 #7
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+5

17, 576,000 / 260,000  = 67.6.... I LOVE my maths  

 Apr 8, 2015
 #8
avatar
0

It's 67.6, I can guarentee it.

 Mar 31, 2016

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