In the parallelogram ABCD, it is given that 3BE = 2DC and area of △DQC = 36 units^2.
Find the area of triangle △BQE.
+23246 The two triangles, EBQ and CDQ are similar by A-A-A.
Thus, the areas of the triangles are in the ratio of the squares of the corresponding sides.
Since 3BE = 2DC, BE = (2/3)DC and the ratio of the areas of triangle(EBQ) and triangle(CDQ)
is 4/9.
Since triangle(QDC) has area 36, triangle(EBQ) has area (4/9)·36 = 16.
