+0  
 
+1
312
2
avatar

1. 

Sam puts $1.25 into his piggy bank in January 2013. Each month he increases how much he puts in by 4 cents.

 How much money will he put in his piggy bank in April 2016?

A)$157.25

B)$16.85

C)$3.35

D)$2.81                                                                                                                                     2. 

Sarah's yearly salary is based on a geometric sequence. Her yearly salaries for her first three years are $34,000 , $35,020, and $36,070.60

 What will be her yearly salary for her 7th year?

A)$41,140

B)$40,000

C)$40,597.78

D)$41,815.71

Guest Dec 14, 2017
 #1
avatar
+1

1.

 

There are 39 months between January 2013 and April 2016.

39 x 0.04 cents =$1.56 - the increase in his saving by April 2016

$1.56 + $1.25 =$2.81 - Amount he must put in his piggy bank in April 2016.

 

2.

 

$34,000 x 1.03^6 =$40,597.78 - Sarah's expected salary by  7th year.

Or, you could use the nth term formula to find the same thing:

Nth. Term = ​F x R^(N - 1)

7th. term =$34,000 x 1.03^6 =$40,597.78 - Which is the same as above.

Guest Dec 14, 2017
 #2
avatar+87334 
+1

2.   Find the common ratio  =

 

35020 / 34000  =   1.03

 

Salary for nth  year   =   34000 (1.03)n-1

 

Salary for the 7th year  =

 

34000(1/03)7-1  =  34000(1.03)6  =  $40597.78

 

 

cool cool cool

CPhill  Dec 14, 2017

14 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.