+0  
 
+1
66
2
avatar+1164 

 Please explain how to solve this in full detail. 

RainbowPanda  Mar 1, 2018
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2+0 Answers

 #1
avatar+86622 
+2

p(x)   is  the answer that goes in the top left box

x cannot be > 1  in this function because we would have a negative under the square root

 

q(x)  is the answer that goes in the bottom left box

x cannot be > -1  ...for instance...if x  = 0, we get -1 under the root which isn't real

 

 

r(x)  goes in the top right box

x cannot be < -1   ...we get a negative under the radical

 

s(x) goes in the bottom right box

If x < 1, we get a negative under the radical

 

I hope I haven't confused you, RP

 

 

cool cool cool

CPhill  Mar 1, 2018
 #2
avatar+1164 
+1

You did not confuse me, thank you so much ^-^

RainbowPanda  Mar 1, 2018

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