need help asap

7   expan  

     contra

    expan

   contra

8   -5 -2 = -7     1/2 of -7 is -3.5      -5 -(-3.5) = -1.5 = x

     3-(-2) = 5    1/2 of 5 is 2.5      3-2.5  = .5   = y

9 3-10 = -7    divided by 5   (3:2 ratio....3+2=5)    -7/5  x 3 =  -  21/5      3-(-21/5) = 36/5 =x

    2-12 = -10   divided by 5  = -2                           -2     x 3 = -6              2-(-6) = 8  = y

(there is ANOTHER point which will divide this line 3:2 ratio...can you find it?)

10  similar to 9

ok here goes

in 7) the first two answers go into contraction without the negative sign and the second two in expansion as they are.

8) midpoint is the point half way between the given points ie (-5+2)/2 for x and (3 + -2)/2 for y

 therefore (-3/2, 1/2) is the midpoint of DE

9) this one is a bit messy   (3,2) and (10,12) 3:2

x values range from 3 to 10 ie distance of 7

y values range from 2 to 12 ie distance of 10

ratio of 3:2 means the point required is 3/5 from A to B along each axis

ie for x :3 + 3/5*7 = 36/5 (or from the opposite direction 10-2/5*7 =36/5 also)

now for y : 2+3/5*10 = 8

so (71/5,8) is the required point

10) same working as 9) answer (11,7)

10)      ( 1,2)  (13, 8)    dividing AB in a 5:1 ratio

So  the line segment is divided into 6 parts.....and the point we are looking for is 5/6 of the way from A to B

[ (1 + ( 13 - 1)(5/6), 2 + (8 - 2)(5/6) ]  =

[ ( 1 + (12)(5/6)  , 2 + (6)(5/6) ]  =

[ 1 + 10, 2 + 5 ]  =

(11, 7)