Find all solutions of the equation(answers)
|x^2 - 14x + 29| = 4
Discuss whether or not your solution generates extraneous solutions.
|x^2 - 14x + 29| = 4
We have that either
x^2 - 14x + 29 = 4 or that x^2 - 14x + 29 = -4 simplify
x^2 - 14x + 25 = 0 x^2 - 14x + 33 = 0 factor
The second equation factors as ( x - 11) ( x - 3) = 0
Setting both factors to 0 and solving for x produces x = 11 and x = 3
For the first equation we can complete the square on x to solve
x^2 - 14x = -25 take 1/2 of 14 = 7....square it = 49....add it to both sides
x^2 - 14x + 49 = -25 + 49 factor the left side....simpify the right
(x - 7)^2 = 24 take both roots
x - 7 = ±√24
x - 7 = ±2√6 add 7 to both sides
x = 7 ±2√6
None of the 4 solutions are extraneous as we can see by this graph....the x axis is intersected four times [ 4 real "zeroes"]
https://www.desmos.com/calculator/8incrgx666
Find all solutions of the equation(answers)
|x^2 - 14x + 29| = 4
\(\begin{array}{|lrclcrcl|} \hline & |x^2 - 14x + 29| &=& 4 \\ \Rightarrow & |(x-7)^2-20| &=& 4 \quad & | \quad \text{substitute} \quad u = (x-7)^2 \\\\ & |u-20| &=& 4 \\ & u_1-20 &=& 4 &\text{ or }& u_2-20 &=& -4 \\ & u_1 &=& 24 && u_2 &=& 16 \\ \hline \end{array} \)
\(\begin{array}{|rcll|} \hline u &=& (x-7)^2 \\ \pm\sqrt{u} &=& x-7 \\ 7 \pm\sqrt{u} &=& x \\ \mathbf{x} & \mathbf{=} & \mathbf{7 \pm\sqrt{u}} \\ \hline \end{array}\)
Solutions:
\(\begin{array}{|rclcl|} \hline x_1 &=& 7+\sqrt{u_1} = 7 + \sqrt{24} &=& 7+2\sqrt{6} \\ x_2 &=& 7-\sqrt{u_1} = 7 - \sqrt{24} &=& 7-2\sqrt{6} \\ x_3 &=& 7+\sqrt{u_2} = 7 + \sqrt{16} &=& 11 \\ x_4 &=& 7-\sqrt{u_2} = 7 - \sqrt{16} &=& 3 \\ \hline \end{array}\)
Proof:
\(\begin{array}{|rcll|} \hline |(7+2\sqrt{6})^2 - 14\cdot (7+2\sqrt{6}) + 29| &=& 4 \\ |11.8989794856^2 - 14\cdot 11.8989794856 + 29| &=& 4 \\ |-25 + 29| &=& 4 \\ |4| &=& 4 \\ 4 &=& 4 \ \checkmark \\\\ \hline |(7-2\sqrt{6})^2 - 14\cdot (7-2\sqrt{6}) + 29| &=& 4 \\ |2.10102051443^2 - 14\cdot 2.10102051443 + 29| &=& 4 \\ |-25 + 29| &=& 4 \\ |4| &=& 4 \\ 4 &=& 4 \ \checkmark \\\\ \hline |11^2 - 14\cdot 11 + 29| &=& 4 \\ |121 - 154 + 29| &=& 4 \\ |-33 + 29| &=& 4 \\ |-4| &=& 4 \\ 4 &=& 4 \ \checkmark \\\\ \hline |3^2 - 14\cdot 3 + 29| &=& 4 \\ |9 - 42 + 29| &=& 4 \\ |-33 + 29| &=& 4 \\ |-4| &=& 4 \\ 4 &=& 4 \ \checkmark \\ \hline \end{array}\)