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Given a^2-b^2=997 where "a" and "b" are both integers and 997 is a prime number, what is the value of ab?
 

Any help is appreciated!!!

 Aug 12, 2019
 #1
avatar+5788 
+2

\(a^2 - b^2 = 997\\ (a-b)(a+b) = 997\\~\\ \text{Now factor $997$ to see what we're working with}\\ 997 = \text{Prime!}\\ a-b=1\\ a+b = 997\\ a=499,~b=498\\\)

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 Aug 12, 2019
 #2
avatar+771 
+3

very good rom

travisio  Aug 12, 2019

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