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# Need help asap!!!!!

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Given a^2-b^2=997 where "a" and "b" are both integers and 997 is a prime number, what is the value of ab?

Any help is appreciated!!!

Aug 12, 2019

#1
+6180
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$$a^2 - b^2 = 997\\ (a-b)(a+b) = 997\\~\\ \text{Now factor 997 to see what we're working with}\\ 997 = \text{Prime!}\\ a-b=1\\ a+b = 997\\ a=499,~b=498\\$$

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Aug 12, 2019
#2
+792
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very good rom

travisio  Aug 12, 2019