A quadratic of the form $-2x^2 + bx + c$ has roots of $x = 3 + \sqrt{5}$ and $x = 3 - \sqrt{5}.$ The graph of $y = -2x^2 + bx + c$ is a parabola. Find the vertex of this parabola.
ignoring dollar sign glitch,
your polynomials is -2[(x-(3+root5)(x-(3-root5)]
simplyfing
p(x)=-2(x^2-6x+4)
vertex coordinates are (-b/2a, -d/4a)
so vertex is V(3,10)
CALCUALTION : X = -b/2a=-(-6)/2=3
Y= -D/4a=-(20)/2=10
+8 
