A quadratic of the form −2x2+bx+c has roots of x=3+√5 and x=3−√5. The graph of y=−2x2+bx+c is a parabola. Find the vertex of this parabola.
ignoring dollar sign glitch,
your polynomials is -2[(x-(3+root5)(x-(3-root5)]
simplyfing
p(x)=-2(x^2-6x+4)
vertex coordinates are (-b/2a, -d/4a)
so vertex is V(3,10)
CALCUALTION : X = -b/2a=-(-6)/2=3
Y= -D/4a=-(20)/2=10
+8 
