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-4
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the graph of $y = ax^2 + bx + c$ is shown below. Find a*b*c (The distance between the grid lines is one unit.)

 

 

 

 

2.

The line x=4   is an axis of symmetry of the graph ax^2+bx+c  Find a*b*c

 

3. Find the vertex of the graph of the equation y=-2x^2+8x+15

 

 

4. The parabola  is graphed below. Find  a+b+c . (The grid lines are one unit apart.) 

 

FIRST GRAPH FIRST QUESTION SECOND GRAPH  4TH QUESTION

thx for help in advance

 Jul 1, 2020
 #1
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1. The equation of the parabola is y = 1/3*x^2 - x + 4/3, so abc = (1/3)(-1)(4/3) = -4/9.

 

3. y = -2x^2 + 8x + 15

 

(complete square) y = -2(x - 4)^2 + 47 ==> vertex = (4,47)

 Jul 1, 2020
 #2
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-4

you were wrong sorry

NIbberlat  Jul 1, 2020

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