I tried doing ti myself but I feel like I am way off. I think 1 is B and 2 is C

Forty slips of paper are numbered 1 through 40 and are distributed among a group of people. A random number generator is used to select a single number between 1 and 40, inclusively.

A fair decision is made using this process.

How many people could be in this group?

6

8

12

15

In a particular game, a spinner with four equally-sized sectors labeled 1, 4, 6, and 8 is spun twice. One turn is considered 2 spins of the spinner.

If the sum of the spins is even, you move forward 6 spaces. Otherwise, you move back 2 spaces.

What is the mathematical expectation for the number of spaces moved in one turn?

3 spaces backward

1 space backward

3 spaces forward

1 space forward

jjennylove Apr 30, 2019

#1**+1 **

1) The number of people in the group must divide 40. 8 is the only selection that divides 40.

2)

Even sum pairs are (1,1),(4,4),(4,6),(4,8),(6,4),(6,6),(6,8),(8,4),(8,6),(8,8) - There are 10 of them

Odd sum pairs are (1,4),(1,6),(1,8),(4,1),(6,1),(8,1) - There are 6 of them

P[Even]=10/16 = 5/8

P[Odd]=6/16 = 3/8

E[moves] = 5/8 x 6 - 3/8 x 2 = (30-6)/8 = 3 = 3 spaces forward

Rom Apr 30, 2019

#1**+1 **

Best Answer

1) The number of people in the group must divide 40. 8 is the only selection that divides 40.

2)

Even sum pairs are (1,1),(4,4),(4,6),(4,8),(6,4),(6,6),(6,8),(8,4),(8,6),(8,8) - There are 10 of them

Odd sum pairs are (1,4),(1,6),(1,8),(4,1),(6,1),(8,1) - There are 6 of them

P[Even]=10/16 = 5/8

P[Odd]=6/16 = 3/8

E[moves] = 5/8 x 6 - 3/8 x 2 = (30-6)/8 = 3 = 3 spaces forward

Rom Apr 30, 2019