Find all values of x such that \(\sqrt{4x^2} - \sqrt{x^2} = 6\)

Please help me asap! I appreciate your help!

CPhill said that it is:

sqrt (4x^2) - sqrt (x^2) = 6 we can write

2sqrt (x^2) - sqrt (x^2) = 6

sqrt (x^2) = 6 square both sides

x^2 = 36 take both roots

x = ± 6

When i put in the answer, the website said that 6 is incorrect. Can anybody clarify/ tell me the new answer?

Web2.0CalcUser123 Nov 3, 2018

#1**+2 **

A little different approach might work:

sqrt (4x^2) = +- 2x

sqrt(x^2) = +- x

so it could be

-2x-x = 6 x= -2

-2x+x = 6 x = -6

2x-x = 6 x= 6

2x+x = 6 x = 2 2 and -2 won't work, but 6 and -6 should work

ElectricPavlov Nov 4, 2018