+0  
 
+1
212
2
avatar

Need help on this problem im kinda stuck

 

 Sep 5, 2019
 #1
avatar
+1

Complete the square:
p^2 + 10 p = 1

Move everything to the left hand side.
Subtract 1 from both sides:
p^2 + 10 p - 1 = 0

Move the constant term to the right hand side.
Add 1 to both sides:
p^2 + 10 p = 1

Group terms together on the left hand side.
Group terms together on the left hand side, with a placeholder constant:
(p^2 + 10 p + __) = __ + 1

Find the appropriate term to place inside (p^2 + 10 p + __).
Take one half of the coefficient of p and square it, then add it to both sides.
Add (10/2)^2 = 25 to both sides:
(p^2 + 10 p + 25) = 25 + 1
(p^2 + 10 p + 25) = 26

Express p^2 + 10 p + 25 as a square.
p^2 + 10 p + 25 = (p + 5)^2:
(p + 5)^2 = 26

 Sep 5, 2019
 #2
avatar+111389 
+1

p^2 + 10p   + _____   =   1 +   _____

 

Take (1/2)  of 10   = 5.....square it  = 25.....this is the number that goes in both blanks

 

p^2 + 10p +  25    =  1 +  25          factor the left  side, simplify the right

 

(p + 5)^2  =  26                     take both roots

 

p + 5  =  ±√26              subtract 5 from both sides

 

p  =  -5 ±√26

 

 

 

cool cool cool

 Sep 5, 2019

6 Online Users