A pyramid is formed on a 6x8 rectangular base. The four edges joining the apex to the corners of the rectangular base each have length 13. What is the volume of the pyramid?

Starz Jan 13, 2019

#1**+1 **

Need to find h the height of the pyramid....then volume = lwh/3

the diagonal of the base (using Pythag Theorem) sqrt(6^2 + 8^2) = 10

now the mid point of the diagonal and h form another right triangle with hypotenuse 13 (given)

so use pythag theorem again to find h h^2 + 5^2 = 13^2 yields h = 12

Volume = lwh/3 = (6)(8)(12)/3 = 192 units^3

ElectricPavlov Jan 13, 2019

#1**+1 **

Best Answer

Need to find h the height of the pyramid....then volume = lwh/3

the diagonal of the base (using Pythag Theorem) sqrt(6^2 + 8^2) = 10

now the mid point of the diagonal and h form another right triangle with hypotenuse 13 (given)

so use pythag theorem again to find h h^2 + 5^2 = 13^2 yields h = 12

Volume = lwh/3 = (6)(8)(12)/3 = 192 units^3

ElectricPavlov Jan 13, 2019