+36 A pyramid is formed on a 6x8 rectangular base. The four edges joining the apex to the corners of the rectangular base each have length 13. What is the volume of the pyramid?
+36916 Need to find h the height of the pyramid....then volume = lwh/3
the diagonal of the base (using Pythag Theorem) sqrt(6^2 + 8^2) = 10
now the mid point of the diagonal and h form another right triangle with hypotenuse 13 (given)
so use pythag theorem again to find h h^2 + 5^2 = 13^2 yields h = 12
Volume = lwh/3 = (6)(8)(12)/3 = 192 units^3
+36916 Need to find h the height of the pyramid....then volume = lwh/3
the diagonal of the base (using Pythag Theorem) sqrt(6^2 + 8^2) = 10
now the mid point of the diagonal and h form another right triangle with hypotenuse 13 (given)
so use pythag theorem again to find h h^2 + 5^2 = 13^2 yields h = 12
Volume = lwh/3 = (6)(8)(12)/3 = 192 units^3
