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Let a = (1,2) and b = (5;-1) be two vectors. Compute and draw the vector a-3b

 Sep 3, 2015

Best Answer 

 #1
avatar+223 
+5

Look at this, 

 

Let c = (x1,y1) and d = (x2,y2)

 

c+d = (x1+x2,y1+y2) 

 

λ(x,y)= (λx,λy) where λ is any number

 

and as always the multiplication will be executed before addition. 

 

Good luck and please ask again if you didn't get it:))

 Sep 3, 2015
 #1
avatar+223 
+5
Best Answer

Look at this, 

 

Let c = (x1,y1) and d = (x2,y2)

 

c+d = (x1+x2,y1+y2) 

 

λ(x,y)= (λx,λy) where λ is any number

 

and as always the multiplication will be executed before addition. 

 

Good luck and please ask again if you didn't get it:))

Headingnorth Sep 3, 2015
 #2
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0

headingnorth:

Would it then in this scenario be a+b=(6,1)

and in this case since its -3b I would multiply 5 and -1 with 3.

3b = (15, -3)

and a= (1,2)

 

or would I use the a+b=6,1) so a-3b = 6-(3*1)

 Sep 3, 2015
 #3
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0

Would the answer be (-14,5) as (1,2)-(15,-3) is equal to (-14,5)

 Sep 3, 2015
 #4
avatar+223 
+5

Yes the firs one is right so just add them:)

 Sep 3, 2015

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