The value of y varies inversely as \(\sqrt x \) and when x=24, y=15. What is x when y = 3?
Since y and \(\sqrt{x}\) are inversely proportional, this means that \(y\sqrt{x}=k\) for some constant k. Substituting the given values, when x=24 and y=15, we find that \(15\sqrt{24}=k\). Therefore, when y=3, we can solve for x:
\(\begin{align*} 3\cdot\sqrt{x}&=15\sqrt{24}\\ \Rightarrow\qquad 9x=5400\\ \Rightarrow\qquad x&=\boxed{600} \end{align*}\)