If $a = 4$, $b = 2$, and $c = -5$, then what is the value of $\sqrt[3]{4a^4b^5} + \dfrac{a - c}{(b+c)^2}$?
Plug in the values: 3√4a4b5+a−c(b+c)2
=3√4(4)4(2)5+(4)−(−5)((2)+(−5))2
=3√1024⋅32+9(−3)2
=3√32768+99
=32+1
=33
EZ the best answer ever THANK U
No problemo :D
+592 
