I'm not sure if I graphed this correctly, according to the information provided. :|
I also need help w/ this Question.
Thanks!
The first one is close
We have the form y = Asin (Bx) + C
A = the amplitude = 3
We can find B thusly:
B = 2pi / period = 2pi / 4 = pi/2
C = the shift up/down ..... the normal midline for the sine is y = 0
This is shifted down 1 unit...so C = -1
So....our function is
y = 3sin (pi/2 x) - 1
Here is the graph : https://www.desmos.com/calculator/5s6jufmy5k
Second one
We have the form y = Asin (Bx) + C
A = the amplitude = 2
Frequency = 1 /period = 1 / (1/ 6pi) = 6pi
B = 2pi/ period = 2pi / 6pi = (1/3)
C = shift up/down
The normal midline is y = 0
y = 3 = shift up by 3 units.....so C = 3
The function is
y = 2sin ( 1/3 x) + 3
Here is the graph : https://www.desmos.com/calculator/7erjhkrwuz