I'm not sure if I graphed this correctly, according to the information provided. :|

I also need help w/ this Question.

Thanks!

Guest Feb 26, 2019

#1**+2 **

The first one is close

We have the form y = Asin (Bx) + C

A = the amplitude = 3

We can find B thusly:

B = 2pi / period = 2pi / 4 = pi/2

C = the shift up/down ..... the normal midline for the sine is y = 0

This is shifted down 1 unit...so C = -1

So....our function is

y = 3sin (pi/2 x) - 1

Here is the graph : https://www.desmos.com/calculator/5s6jufmy5k

CPhill Feb 26, 2019

#2**+2 **

Second one

We have the form y = Asin (Bx) + C

A = the amplitude = 2

Frequency = 1 /period = 1 / (1/ 6pi) = 6pi

B = 2pi/ period = 2pi / 6pi = (1/3)

C = shift up/down

The normal midline is y = 0

y = 3 = shift up by 3 units.....so C = 3

The function is

y = 2sin ( 1/3 x) + 3

Here is the graph : https://www.desmos.com/calculator/7erjhkrwuz

CPhill Feb 26, 2019