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I'm not sure if I graphed this correctly, according to the information provided. :|

 

 

 

I also need help w/ this Question.

 

 

Thanks!


 

 Feb 26, 2019
 #1
avatar+98060 
+2

The first one is close

 

We have the form     y = Asin (Bx) + C

 

A = the amplitude  = 3

 

We can find B  thusly:

 

B = 2pi / period =  2pi / 4  =   pi/2

 

C = the shift up/down ..... the normal midline for the sine is y = 0

This is shifted down 1 unit...so  C = -1

 

So....our function is

 

y =  3sin (pi/2 x) - 1

 

Here is the graph : https://www.desmos.com/calculator/5s6jufmy5k

 

 

cool coolcool

 Feb 26, 2019
 #2
avatar+98060 
+2

Second one

 

We have the form   y = Asin (Bx) + C

 

A = the amplitude  = 2

 

Frequency =  1 /period  =  1 / (1/ 6pi)  =  6pi

 

B  =   2pi/ period =   2pi / 6pi    =  (1/3)

 

C = shift up/down

The normal midline is y = 0

y = 3  = shift up by 3 units.....so C = 3

 

The function is

 

y = 2sin ( 1/3 x) + 3

 

Here is the graph :  https://www.desmos.com/calculator/7erjhkrwuz

 

 

cool cool cool

 Feb 26, 2019
 #3
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0

Thanks for the help on the first one! Did you see my second question?

 

Here it is again in case you missed it.

 

Thanks!

 Feb 26, 2019

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