Probability of Tom playing is 0.6 if he is selected his probability for scoring is 0.8.

the probability of Jerry scoring is 0.45

so we have the following diagram

0.6-Tom playing - 0.6 -> score -0.4 -> not score

0.4 Jerry playing - 0.45-> score -o.gg -> not score

so

If jerry plays in the next two succesive games calculate the probability of him scoring in just one of the matches.

So what i did was multiply the probabilities :

(0.4*0.45*0.4*0.55) = 0.039

However the book gives me a different answer on the back , it says 0.495

What am i doing wrong? does the book have a mistake?

Guest Sep 18, 2017