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It takes 3.78 J of work to stretch a Hooke’s-law spring 14.2 cm from its unstressed length. How much the extra work is required to stretch it an additional 11.2 cm? Answer in units of J.

 Apr 2, 2020
 #2
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It's a direct proportion:  J/cm  =  J/cm

    3.78 J / 14.2 cm  =  (3.78 + x) J / (14.2 + 11.2) cm

    3.78 J / 14.2 cm  =  (3.78 + x) J / 25.4 cm

 

Cross-multiply:  3.78 J · 25.4 cm  =  14.2 cm · (3.78 + x)

 

Solving for x:  x  =  2.98

 Apr 2, 2020

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