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A chemist wishes to make 5 liters of an 7% acid solution by mixing a 10% acidsolution and a 5% acid solution. How many liters of each solution the chemist have to use?

 Sep 20, 2020
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Let the number of Liters of 10% acid that is needed =T

Then, the numbers of Liters of 5% acid that is needed =5 - T

 

0.10T  +  0.05*[5 - T] =0.07 * 5, solve for T

 

T = 2 Liters of 10% acid

5 - 2 = 3 Liters of 5% acid.

 Sep 20, 2020

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