A chemist wishes to make 5 liters of an 7% acid solution by mixing a 10% acidsolution and a 5% acid solution. How many liters of each solution the chemist have to use?
Let the number of Liters of 10% acid that is needed =T
Then, the numbers of Liters of 5% acid that is needed =5 - T
0.10T + 0.05*[5 - T] =0.07 * 5, solve for T
T = 2 Liters of 10% acid
5 - 2 = 3 Liters of 5% acid.
