Triangle ABC has coodinates A=(−4,0), B=(4,0), and C=(0,3).
Let P be the point in the first quadrant such that △ABP has half the area of △ABC but both triangles have the same perimeter.
What is the length of CP?
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Perimeter of ΔABC = 18 units and the area = 12 square units.
AB = 8
AP = 8.4641
BP = 1.5359
AB + AP + BP = 8 + 8.4641 + 1.5359 = 18
Area of ΔABP = 6 u2
CP ≈ 4.582456 units
