The Boomtown Bears are playing against the Tipton Toros in a baseball tournament. The winner of the tournament is the first team that wins three games. The Bears have a probability of 1/5 of winning each game. Find the probability that the Bears win the tournament.
+34 Well, if there is only 3 games, and 1/5 probability for each, I believe you just do:
1/5 * 1/5 * 1/5
= 1/125 probability that the Bears actually win the tournament.
However, if I am wrong, please tell me, as I would be happy to learn what my mistake was and how I could have corrected it!
+118680 Nice try Mmm but you forgot some of the posibilities 
The Boomtown Bears are playing against the Tipton Toros in a baseball tournament. The winner of the tournament is the first team that wins three games. The Bears have a probability of 1/5 of winning each game. Find the probability that the Bears win the tournament.
I will assume that it is imposible to draw.
P(B wins) = 1/5
P(B wines 3 games out of 3) = 1/ 5^3 = 25 / 5^5
P(B wins 3 games out of 4) = 4C3 * (1/5)^3 * (4/5) = 4 * 4 / 5^4 = 16 / 5^4 = 80 / 5^5
P ( B wins 3 games out of 5) = 5C3 * (1/5)^3 *( 4/5)^2 = 10 * 16 / 5^5 = 160 / 5^5
add them together 25+80+160 = 265
265 / 5^5 simplifies to 53/625 = 0.0848
So the prob that the bears win is 8.48%
