If A and B are the roots of the equation 3x^2 + 2x - 3 = 0, where B < A, find the value of each of the following.
a. 1/A + 1/B =
b. A^2 + B^2 =
c. A - B =
d. A^3 - B^3 =
+46 Using the quadratic formula, \(A = \frac{-1}{3} + \frac{\sqrt{10}}{3}\) and \(B = \frac{-1}{3} - \frac{\sqrt{10}}{3}\). Try to do the rest on your own.
