For certain values of k and m, the system
3a + 2b = 2
6a + 2b = k + 3a + mb
has infinitely many solutions (a,b). What are k and m?
Simplify as
3a + (2 - m)b = k
For this to have infinite solutions, the equations must be the same
This implies that m = 0 and k = 2
+1839 
