+0

# need help

0
178
1

The equation y = -6t^2 + 51t describes the height (in feet) of a projectile launched from the surface of Mars at 51 feet per second. In how many seconds will the projectile first reach 100 feet in height?

Jul 6, 2021

#1
+238
+1

This means y = 100

$$-6t^2+51 = 100$$

$$-6t^2+51 =100 = 0$$

Apply quadratic formula to get the positive solution of $$\frac{17}{4}+\frac{\sqrt{201}}{12}$$

Jul 6, 2021

#1
+238
+1
$$-6t^2+51 = 100$$
$$-6t^2+51 =100 = 0$$
Apply quadratic formula to get the positive solution of $$\frac{17}{4}+\frac{\sqrt{201}}{12}$$