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The equation y = -6t^2 + 51t describes the height (in feet) of a projectile launched from the surface of Mars at 51 feet per second. In how many seconds will the projectile first reach 100 feet in height?

 Jul 6, 2021

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 #1
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This means y = 100

\(-6t^2+51 = 100\)

\(-6t^2+51 =100 = 0\)

Apply quadratic formula to get the positive solution of \(\frac{17}{4}+\frac{\sqrt{201}}{12}\)

 Jul 6, 2021
 #1
avatar+234 
+1
Best Answer

This means y = 100

\(-6t^2+51 = 100\)

\(-6t^2+51 =100 = 0\)

Apply quadratic formula to get the positive solution of \(\frac{17}{4}+\frac{\sqrt{201}}{12}\)

Awesomeguy Jul 6, 2021

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