The height h in feet of an object shot straight up with initial velocity v in feet per second is given by h = −16t^2 + vt + c, where c is the initial height of the object above the ground. A model rocket is shot vertically up from a height of 6 feet above the ground with an initial velocity of 22 feet per second. Will it reach a height of 10 feet? Identify the correct explanation for your answer.

Guest Aug 11, 2021

#1**+1 **

c = 6 v = 22

h = - 16t^2 + 22t + 6

10 = - 16t^2 + 22t + 6

-16t^2 + 22t -4 = 0 Use quadratic formula to find t = .215 and 1.15 sec

so yes, it will reach 10 ft as we have times for it on the way up and down

ElectricPavlov Aug 11, 2021