+0  
 
0
47
1
avatar

The height h in feet of an object shot straight up with initial velocity v in feet per second is given by h = −16t^2 + vt + c, where c is the initial height of the object above the ground. A model rocket is shot vertically up from a height of 6 feet above the ground with an initial velocity of 22 feet per second. Will it reach a height of 10 feet? Identify the correct explanation for your answer.

 Aug 11, 2021
 #1
avatar+34374 
+1

c = 6      v = 22       

 

h = - 16t^2 + 22t + 6

 

10 = - 16t^2 + 22t  + 6

-16t^2 + 22t -4 = 0       Use quadratic formula to find t = .215    and     1.15     sec    

                                          so yes, it will reach 10 ft as we have times for it on the way up and down

 Aug 11, 2021

39 Online Users