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$2\sqrt[3]{2}$ is the sixth root of what positive whole number?

Guest Feb 5, 2019

CPhill · Answer 1 · 2019-02-05T03:38:08

Just raise this to the 6th power and we have

( 2 * 2^(1/3) )^6 =

2^6 * (2^(1/3))^6 = { remember that (a^m)^n = a^(m*n) }

64 * 2^2 =

64 * 4 =

256

CoolStuffYT · Answer 2 · 2019-02-05T07:03:20

That means we want to find $(2\sqrt[3]2)^6$ .

We can see that $2^6=64$ and $(\sqrt[3]2)^6=2\times 2=4$

So, $64\times 4=256$ .

You are very welcome!
:P