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\(2\sqrt[3]{2}\) is the sixth root of what positive whole number?

 Feb 5, 2019
 #1
avatar+101870 
+1

Just raise this to the 6th power and we have

 

( 2 * 2^(1/3) )^6   =

 

2^6 *  (2^(1/3))^6 =     { remember  that  (a^m)^n  =  a^(m*n)  }

 

64  *  2^2 = 

 

64 * 4 =

 

256

 

 

cool cool cool

 Feb 5, 2019
 #2
avatar+721 
-1

That means we want to find \((2\sqrt[3]2)^6\).

We can see that \(2^6=64\) and \((\sqrt[3]2)^6=2\times 2=4\)

So, \(64\times 4=256\).

 

You are very welcome!
:P

 Feb 5, 2019

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