+129852 Just raise this to the 6th power and we have
( 2 * 2^(1/3) )^6 =
2^6 * (2^(1/3))^6 = { remember that (a^m)^n = a^(m*n) }
64 * 2^2 =
64 * 4 =
256
+1252 That means we want to find \((2\sqrt[3]2)^6\).
We can see that \(2^6=64\) and \((\sqrt[3]2)^6=2\times 2=4\)
So, \(64\times 4=256\).
You are very welcome!
:P
