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find 3 positive consecutive integers such that the product of the first and the third integer is 17 more than three times the second integer

 Sep 16, 2021
 #1
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Integers     x-1     x       x+1

 

 

(x+1)(x-1) =3x + 17

x^2 -1 -17-3x = 0

x^2 -3x - 18 = 0

(x-6)(x+3)                  x = 6     or -3            5 6 7           ( or    -4 -3 -2   <==== negative integers solution)

 Sep 16, 2021
edited by ElectricPavlov  Sep 16, 2021

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