find 3 positive consecutive integers such that the product of the first and the third integer is 17 more than three times the second integer
+36916 Integers x-1 x x+1
(x+1)(x-1) =3x + 17
x^2 -1 -17-3x = 0
x^2 -3x - 18 = 0
(x-6)(x+3) x = 6 or -3 5 6 7 ( or -4 -3 -2 <==== negative integers solution)
