For what constant k is 1 the minimum value of the quadratic 3x^2 - 16x + k over all real values of x?
+36916 Bowl shaped parabola.....minimum point is the vertex....to find the x value of the vertex
-b/2a = x of the vertex
16/6 sub in this for 'x' to find k which makes the equation = to 1
3 (16/6)^2 - 16 (16/6) + k = 1 k = 22 1/3
