Find all values of b such that (2b−5)x^2−2(b+1)x+3=0 has a real root.
The discriminant of the quadratic formula must = 0 to have only one root
b^2 - 4ac = 0
b in the quadratic formula for this case is -2b+2 a is 2b-5 c is 3
Plug these values into the red equation to find b = 4
+79 
