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Find all values of b such that (2b−5)x^2−2(b+1)x+3=0 has a real root.

 May 27, 2021
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The discriminant of the quadratic formula must = 0 to have only one root

b^2 - 4ac = 0

 

b in the quadratic formula for this case is -2b+2      a is 2b-5     c is 3  

 

Plug these values into the red equation to find  b = 4

 May 27, 2021
edited by imbadatmath  May 27, 2021

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