How many integer solutions for (a, b) satisfied the following equation
a^2+b^2=ab^2
+678 Hello Guest,
How many integer solutions for (a, b) satisfied the following equation
a^2+b^2=ab^2
\(a^2+b^2=ab^2\)
\((a, \mbox { } b) = (2, \mbox {} \pm \mbox { } 2) \)
\((a, \mbox { } b) = ( \pm \mbox { } 2, \mbox { } 2)\)
\((a, \mbox { } b) = (0, \mbox { } 0)\)
Hope this was helpful . . . ^^
!
+118687 Fist thing I did was graph it.
https://www.geogebra.org/classic/svfrstbf
a^2+b^2=ab^2
its symetrical so I want to look at the top half b>0 (then I will double the number of answers)
\(a^2=ab^2-b^2\\ a^2=b^2(a-1)\\ b=\frac{a}{\sqrt{a-1}} \)
a has to be greater than 1,
For b to be an integer
a^2 = k (a-1) where k is an integer
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yea I don't know.
There are at least 2 answers.
