Find the number of integers n that satisfy n2<64−20n−n2.
The given inequality is equivalent to n2<64−20n, or 2n2+20n−64<0. Factoring the left side, we get 2(n−4)(n+8)<0. Since n−4 n>−8. Thus, the possible values of n are −7,−6,−5,…,3,2.
There are 3+(−7)+1=15 integers in this range.
