+0  
 
0
49
1
avatar

Alice and Bob each have a certain amount of money. If Alice receives n dollars from Bob, then she will have 4 times as much money as Bob. If, on the other hand, she gives n dollars to Bob, then she will have 8 times as much money as Bob. If neither gives the other any money, what is the ratio of the amount of money Alice has to the amount Bob has?

 Jul 14, 2023
 #1
avatar+2 
0

This is quite interesting so here is my answer: octordle unlimited

 

Let's denote:

A = the amount of money Alice currently has. B = the amount of money Bob currently has.

Given in the problem:

If Alice receives n dollars from Bob, she will have 4 times as much money as Bob. This means A + n = 4(B - n). If Alice gives n dollars to Bob, she will have 8 times as much money as Bob. This means A - n = 8(B + n).

Now we have two equations, and we can solve for n in terms of A and B:

n = (A - 4B) / 5

n = (A - 8B) / -7

Since both expressions equal n, we can equate and solve for the ratio of A to B:

(A - 4B) / 5 = (A - 8B) / -7

Solving this equation gives us:

-7A + 28B = 5A - 40B 12A = 68B A/B = 68/12 = 17/3

So, the ratio of the amount of money Alice has to the amount Bob has is 17:3.

 Jul 14, 2023

1 Online Users