If the unit value of the square root of 17 is represented as x and its (sq root 17) decimal value is represented by y, x^2+(1/y)?

ISmellGood
Oct 6, 2017

#1**+1 **

If the unit value of the square root of 17 is represented as x and its (sq root 17) decimal value is represented by y, x^2+(1/y)?

I will try and understand what you have said first.

\(x=\sqrt{17} = 17^{0.5}\\ y=\sqrt{\sqrt{17}}=17^{0.25}\\ x^2+\frac{1}{y}\\=17+\frac{1}{17^{0.25}}\\\approx 17+\frac{1}{2.0305431848689307}\\\approx17.4924790605054523308\)

Melody
Oct 7, 2017

#4**+1 **

Sorry that it wasn't clear enough, I had to translate the question as best as I could from Chinese and naturally I'm not a native speaker of English! What I meant by the unit value was the number before the decimal point.

ISmellGood
Oct 8, 2017

#5**0 **

Say a number is 6.126543

Then 6 is the floor value

OR

6 is the number rounded down to the nearest integer.

Just so you will know for next time

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A question for someone else. Maybe Alan

What is the** floor value** of -6.5 [Or any number between -7 and -6]

I assume it is -7, is that correct ?

Melody
Oct 8, 2017