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If the unit value of the square root of 17 is represented as x and its (sq root 17) decimal value is represented by y,  x^2+(1/y)?

ISmellGood  Oct 6, 2017
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 #1
avatar+90581 
+1

If the unit value of the square root of 17 is represented as x and its (sq root 17) decimal value is represented by y,  x^2+(1/y)?

 

I will try and understand what you have said first.

\(x=\sqrt{17} = 17^{0.5}\\ y=\sqrt{\sqrt{17}}=17^{0.25}\\ x^2+\frac{1}{y}\\=17+\frac{1}{17^{0.25}}\\\approx 17+\frac{1}{2.0305431848689307}\\\approx17.4924790605054523308\)

Melody  Oct 7, 2017
 #2
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What do you mean by unit value and decimal value?

Melody  Oct 7, 2017
 #4
avatar+222 
+1

Sorry that it wasn't clear enough, I had to translate the question as best as I could from Chinese and naturally I'm not a native speaker of English! What I meant by the unit value was the number before the decimal point. laugh

ISmellGood  Oct 8, 2017
 #5
avatar+90581 
0

Say a  number is       6.126543

 

Then 6 is the floor value

OR

6 is the number rounded down to the nearest integer. 

 

Just so you will know for next time

 

----------------------------

 

A question for someone else.  Maybe Alan 

 

What is the floor value of       -6.5                   [Or any number between -7 and -6]

I assume it is -7, is that correct ?

Melody  Oct 8, 2017
 #6
avatar+26242 
+1

"What is the floor value of       -6.5                   [Or any number between -7 and -6]

I assume it is -7, is that correct ?"

 

Correct!

Alan  Oct 8, 2017
 #7
avatar+90581 
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Thanks Alan :)

Melody  Oct 8, 2017
 #3
avatar+26242 
+1

My interpretation of this is that the "unit value" means the integer part ignoring the numbers after the decimal point, and the "decimal value" is the part left after subtracting the "unit value".  So:

 

Alan  Oct 7, 2017

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