Tony rode a bicycle from A to B in 36 \36 km/h. After that, Tony went back from B to A in 48 km/h. It took 3 and a half hours to go from A to B and back to A. Assuming that Tony never have any rest, what is the distance between A and B?
+310 Let thhe distance between A and B be \(d\).
Since distance/speed=time, \(\frac{d}{36}+\frac{d}{48}=\frac{7}{2}\).
Multiplying both sides by 144, we get \(4d+3d=504\)
\(7d=504\)
\(d=72\)
+37146 Distance is 2d
rate x time = distance
36t1 = 48(3.5-t1)
t1 = 2 hrs 2 hrs at 36 km/hr = 72 km
