Write down the quadratic equation whose roots are x = -7 and x = 8 and the coefficient of x^2 is 1.
Enter your answer in the form "x^2 + bx + c = 0".
+171 that is just a little off.
x^2 + bx + c = 0
we know that one solution is -7, and the other one is 8
that means:
$\left. \begin{array}
\ x=-7 \\ x=8
\end{array} \right\} \implies \left. \begin{array}
\ x+7=0 \\ x-8=0
\end{array} \right\} $ knowing that we can write the quadratic as a factorised form$ (x+7)(x-8) $
new lets find the quadratic:
$ (x+7)(x-8) \overset{\left(m+n\right)\left(p-q\right) = mp-mq+np-nq }{=============\Rightarrow} xx+x\left(-8\right)+7x+7\left(-8\right) $
$xx-8x+7x-7\cdot \:8$
$ \boxed{ x^2-x-56 } $
